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Text Solution

Solution :

Since, the vertex of the parabola is (0, 0) and the focus is (0, 5) which lies on y-axis itself is the axis of the parabola. <br> Since the focus lies on the positive side of y-axis therefore, the required equation is of the form `x^(2) = 4ay` <br> Here, a = 5 <br> `therefore x^(2) = 20y` is the required equation. **Conic section introduction**

**Condition to represent pair of lines circle and conic**

**Analytical definition of parabola**

**Equation of parabola in its standard form**

**Various results of standard equation of parabola**

**Tabular representation of all standard forms of parabolas**

**Parabola with axis parallel to coordinate axis**

**Position of point with respect to parabola `y^2=4ax`**

**Parabolic curve **

**What is focal Chord and If the chord joining P`(a(t_1)^2;2at_1)` and Q `(at_2^2;2at_2)` is the focal chord ; then `t_1t_2=-1`**